Question

Please answer it........

Answer 1

Answer:

p,q,r]  

⎝

⎜

⎜

⎛

​  

 

3

3

2

​  

 

4

2

0

​  

 

1

2

3

​  

 

⎠

⎟

⎟

⎞

​  

=[3,0,1]

[3p+3q+2r4p+2qp+3q+2r]=[3,0,1]

3p+3q+2r=3→(i)

4p+2q=0→(ii)

p+3q+2r=1→(iii)

fromeq.(iii)

3q+2r=1−p

​  

 

put the value of 3q+2rineq.(i)

weget

3p+1−p=3

2p=2

p=1

​  

 

Put the value of  P in equation (ii)

4(1)+2q=0

2q=−4

q=−2

​  

 

Put the value of P and Q in equation

3(1)+3(−2)+2r=3

3−6+2r=3

−6=−2r

r=3

find=2p+q−r

=2(1)−2−3

=−3

​  

Step-by-step explanation: