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p,q,r]
⎝
⎜
⎜
⎛
3
3
2
4
2
0
1
2
3
⎠
⎟
⎟
⎞
=[3,0,1]
[3p+3q+2r4p+2qp+3q+2r]=[3,0,1]
3p+3q+2r=3→(i)
4p+2q=0→(ii)
p+3q+2r=1→(iii)
fromeq.(iii)
3q+2r=1−p
put the value of 3q+2rineq.(i)
weget
3p+1−p=3
2p=2
p=1
Put the value of P in equation (ii)
4(1)+2q=0
2q=−4
q=−2
Put the value of P and Q in equation
3(1)+3(−2)+2r=3
3−6+2r=3
−6=−2r
r=3
find=2p+q−r
=2(1)−2−3
=−3
Step-by-step explanation:
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