Question

please answer it ♡♡♡​

Answer 1

Answer:

Given- AB||DC ,AD=BC

To prove- angle A= angle B, angle C= angle D

Proof - In quadrilateral ADCE

(i) angle D= x,angle A= 180°- x [co- interior]

AD||CF , angle ECD=180- x

Now in ∆ CBE

angle CBE= angle CEB= x

angle B+x=180. (l.p)

angle B= 180- x

angle A = angle B = 180- x

so,angle A= angle B=180- x

(ii) angle D= x ,angle BCE= 180- 2x

angle C= 180-x- (180-2x)

so,angle C=180-x-(180-2x)

=180-x-180+2x=x

so,angle C=angle D=x

(iii) In ∆ ABC & ∆ BAD

AD= BC

DB= AB ( common)

angle A=angle B

by SAS

∆ABC congruent to ∆ BPD

AC= BD by CPCT

Answer 2

Answer:

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