Question

please answer it..
❤️​

Answer 1

Explanation:

Let ∠ a = 2x, then ∠b = 3x

(sum of angle in linear pair always equal to 180° )

∠XOM + ∠MOP + ∠POY = 180°

∠b + ∠a + ∠POY = 180°

given that ∠POY = 90°

plug this value we get

3x + 2x + 90° = 180°

5x = 90°

x = 18°

a = 2x = 2 × 18 = 36°

b = 3x = 3 ×18 = 54°

MN is a straight line.

sum of angle in linear pair always equal to 180°

so that ∠b + ∠c = 180°

54° + ∠c = 180°

∠c = 180° − 54° = 126°

∠ c = 126°

Answer 2

Since XOY is a straight line

=> angle XOY =180°= angle POY+a+ b

And angle POY =90°

=> XOY=90°+a+b

=>a+b=180-90=90°

And the ratio of angle a and b is 2:3

=> 2x+3x=90

=>5x=90

=>x=18

=> angle a =2x= 18×2= 36°

=> angle b = 3x =18×3 = 54°