please answer it......
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Method (1):
f(x) = 4x^3 - 12x^2 + 14x - 3
g(x) = 2x - 1.
Now, we should divide f(x) by g(x).
2x^2 - 5x + 9/2
-------------------------------------
2x - 1) 4x^3 - 12x^2 + 14x - 3
4x^3 - 2x^2
-----------------------------------
-10x^2 + 14x - 3
- 10x^2 + 5x
----------------------------------
9x - 3
9x - 9/2
-------------------------------------
3/2
Method 2:
Given f(x) = 4x^3 - 12x^2 + 14x - 3.
Given g(x) = 2x - 1.
By remainder theorem, g(x) = 0
= > 2x - 1 = 0
= > 2x = 1
= > x = 1/2.
Now,
plug x = 1/2, we get
= > 4(1/2)^3 - 12(1/2)^2 + 14(1/2) - 3
Therefore the remainder is 3/2.
Hope this helps!
f(x) = 4x^3 - 12x^2 + 14x - 3
g(x) = 2x - 1.
Now, we should divide f(x) by g(x).
2x^2 - 5x + 9/2
-------------------------------------
2x - 1) 4x^3 - 12x^2 + 14x - 3
4x^3 - 2x^2
-----------------------------------
-10x^2 + 14x - 3
- 10x^2 + 5x
----------------------------------
9x - 3
9x - 9/2
-------------------------------------
3/2
Method 2:
Given f(x) = 4x^3 - 12x^2 + 14x - 3.
Given g(x) = 2x - 1.
By remainder theorem, g(x) = 0
= > 2x - 1 = 0
= > 2x = 1
= > x = 1/2.
Now,
plug x = 1/2, we get
= > 4(1/2)^3 - 12(1/2)^2 + 14(1/2) - 3
Therefore the remainder is 3/2.
Hope this helps!
siddhartharao77:
:-)
Answered by
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Answer:
refer to the attachment above for ur answer
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hope it helps you ^_^
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