Question

please answer it......

Answer 1

Answer:

4

Step-by-step explanation:

$Given:\frac{1}{sin 10}-\frac{\sqrt{3}}{cos10}$

$=>\frac{cos10-\sqrt{3}sin10}{sin10cos10}$

$=>\frac{2[\frac{1}{2}cos10-\frac{\sqrt{3}}{2}sin10]}{sin10cos10}$

Multiply the numerator and denominator by '2', we get

$=> \frac{2*2[\frac{1}{2}cos10-\frac{\sqrt{3}}{2}sin10]}{2sin10cos10}$

We know that 2sinAcosA = sin2A.

$=>\frac{4[sin30cos10-cos30sin10]}{sin 2 * 10}$

We know that sinAcosB-cosAsinB = sin(A-B).

$=>\frac{4[sin(30-10)]}{sin20}$

$=>\frac{4sin20}{sin20}$

$=>4$

Hope it helps!

Answer 2

Answer:

Multiply the numerator and denominator by '2', we get

Step-by-step explanation: