Chemistry, asked by chenxiaxoi, 1 year ago

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Answered by 1402Aryan1402
2

It involves alternate oxidation and reduction of 2-ethylanthraquinol.  First, air is passed through a mixture of 2-ethylanthraquinol mixture. It yields 2-ethylanthraquinone and hydrogen peroxide. The product, 2-ethylanthraquinone, is then reduced. For this, hydrogen under a pressure of 1 to 3 atmospheres at 4oC is passed over 2-ethylanthraquinone. This gives back 2-ethylanthraquinol – the reactant.   This reaction gives a dilute solution of hydrogen peroxide. It is then extracted with water, and the solution of the required concentration is prepared.

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