please answer it
Also please write the logic how you got the answer
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Anonymous:
please answer both
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Let root{6+root[6+root(6+...} = x
=> (root ( 6 + x ) )^2=( x)^2 {squarig both the sides}
the root will be cancel and x is x square
=> (6 + x) = x^2
take 6+x to another side and solve the equation
=> x^2 - x - 6 = 0
Solving this,
x = 3
=> (root ( 6 + x ) )^2=( x)^2 {squarig both the sides}
the root will be cancel and x is x square
=> (6 + x) = x^2
take 6+x to another side and solve the equation
=> x^2 - x - 6 = 0
Solving this,
x = 3
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