please answer it anyone
Attachments:
Answers
Answered by
1
An organic compound has= 5.5 g
N=1.4g
%of N in compound=1.4/5.5*100=25.45%
%of C in compound=3.6/5.5*100=65.45%
%of H in compound=0.5/5.5*100=9.10%
N-25.45-14-25.45/14-1.81-1.81/1.81=1
C-65.45-12-65.45/12-5.45-5.45/1.81=3.02=3
H-9.10-1-9.10/1-9.10/1.81-5.02=5
E.F=NC3H5
E.F. MASS =14+36+5=55
MOLECULAR MASS=55
N=M.F/E.F=55/55=1
M.F=NC3H5(ANSWER)
N=1.4g
%of N in compound=1.4/5.5*100=25.45%
%of C in compound=3.6/5.5*100=65.45%
%of H in compound=0.5/5.5*100=9.10%
N-25.45-14-25.45/14-1.81-1.81/1.81=1
C-65.45-12-65.45/12-5.45-5.45/1.81=3.02=3
H-9.10-1-9.10/1-9.10/1.81-5.02=5
E.F=NC3H5
E.F. MASS =14+36+5=55
MOLECULAR MASS=55
N=M.F/E.F=55/55=1
M.F=NC3H5(ANSWER)
Similar questions