please answer it as early as possible
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Answer:
sin^2 A tan^2 A.
Step-by-step explanation:
From the properties of trigonometric ratios :
- tanA = sinA / cosA
- 1 - cos^2 A = sin^2 A
Here,
⇒ tan^2 A - sin^2 A
⇒ ( tanA )^2 - sin^2 A
⇒ ( sinA / cosA )^2 - sin^2 A
⇒ sin^2 A [ 1 / cos^2 A - 1 ]
⇒ sin^2 A [ ( 1 - cos^2 A ) / cos^2 A ]
⇒ sin^2 [ sin^2 A ] / cos^2 A From above, 1 - cos^2 A = sin^2 A
⇒ sin^2 ( sinA / cosA )^2
⇒ sin^2 A tan^2 A
Proved.
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