Please answer it as fast as possible. The question is from class 9 physics.
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my question is from chemistry
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11
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case 1
a = 2 ms⁻², t = 10
s = ut+at²/2
s = 0[10]+2[100]/2 = 200/2 = 100 m
case 2
v = u+at = 0+2[10] = 20 ms⁻¹ [ velocity after case 1 ]
t = 30
s = vt = 20[30] = 600 m
case 3
u = 20 ms⁻¹ [ velocity after case 2 ]
v = 0 [ comes to rest ]
a = -4 ms⁻²
a = -4
v-u/t = -4
0-20/t = -4
-4t = -20
t = 5
s = ut+at²/2 = 20[5]+[-4]25/2 = 100-50 = 50 m
result
total distance travelled = 100+600+50 = 750 m
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