please answer it as soon as possible
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i think the question is incomplete....(case of dice not mentioned)
(i)the probability of getting an even no in a dice is
no.of favourable events =(2,4,6)=3/
total no of events=6
p(d)=3/6=1/2
(ii) multiples of 3 in dice =(3,6)=2
total no of events=6
so p(d)=2/6=1/3
(iii)no.3 and 4
no of favourable events=(3,4)=2
total no of events=6
p(d)=2/6=1/3
(iv)an odd no.=(1,3,5)
no.of favourable events=3
total no of events=6
p(d)=3/6=1/2
(v)no. of favourable events =(4,5)=2
total no of events=6
p(d)=2/6=1/3
HOPE THIS HELPS IF SO THEN DON'T FORGET TO THANK AND MARK AS BRAINLIEST.........
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