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v = 2 x³+ 2x + 3
dv/dx = 6x²+ 2
a = vdv/dx
a =(2x³+2x+3) (6x²+2)
Now let's substitute value of x = 5
a = (2(5)³+ 2(5) +3) (6(5)²+ 2)
a= 250 +10 + 3 × 150 + 2
a = 262 × 152
a = 39,976 m/s²
a = 39, 976 m/s²
Therefore, acceleration of particle when it covers 5m is 39976 m/s²
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