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Answer:
Sum of angles of a Δ=180
o
For ΔADB
90
o
+45
o
+y=180
o
y=180−135
=45
o
.
For ΔADC
x+40
o
+90
o
=180
o
x=180−90−40
=90−40
=50
o
.
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Angle x = 45 degree
Angle y = 180-45 = 135 degree
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