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Since, the diagonals of a parralelogram bisect each other at 90°.
therefore,
5b-12=3b+12 (Equation 1)
2a+8=8a-16 (Equation 2)
From equation 1,
From equation 2,
therefore,
1 st diagonal =5b-12+3b+2
since, (b=7)
therefore 1st diagonal = 35-12+21+2=46
2nd diagonal=2a+8+8a-16
since, (a=4)
therefore 2nd diagonal = 8+8+32-16=32.
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