Question

please answer it correctly
if
$x ^{2} + 1 \div x^{2}=4 then \: find \: x ^{4} + 1 \div x^{4}$
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Answer 1

Step-by-step explanation:

${x}^{2} + \frac{1}{ {x}^{2} } = 4 \\ = ( {x}^{2} + \frac{1}{ {x}^{2} } ) {}^{2} = (4) {}^{2} \\ {x}^{4} + \frac{1}{ {x}^{4} } + 2 = 16 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 16 - 2 \\ {x}^{4} + \frac{1}{ {x}^{4} } = 14 \: \: \: \: ans.$