Question

Please answer it fast

Answer 1

Answer:

question is nt clear at the boundry of the page so plxx snd it again on brainlyy with good and pure photo

Answer 2

Answer:

1) 1/2λ

N₁ : Undecayed X₁

N₂ : Undecayed X₂

Undecayed material amount is given by:-

N=N₀($e^{-(lambda)t}$)

N₁/N₂ = 1/e= $\frac{e^{-6(lambda)t}}{e^{-4(lambda)t} }$

$e^{-1}=e^{-2(lambda)t}$

$\boxed{t=\frac{1}{2(lambda)}}$

Hope this answer helped you :)