Math, asked by deepakg1964, 8 months ago

please answer it fast...

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Answered by Anonymous

Step-by-step explanation:

LHS

1 + (tan²A / 1 + secA)

tan²A + 1 = sec²A

=> tan²A = sec²A - 1 => (secA - 1)(secA + 1)

Therefore,

1 + (tan²A / 1 + secA)

= 1 + [ (secA - 1)(secA + 1) / ( 1 + secA) ]

(secA + 1) & (1 + secA) will cancel out.

=> 1 + secA - 1

= secA

LHS = RHS

Hence proved

Answered by jatt714

answer is in attachment

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