Question

please answer it fast.. ​

Answer 1

Explanation:

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Answer 2

According to the velocity-time graph, we are asked to calculate the distance in first 10 seconds.

Explanation: We know that in a velocity time graph the area under the curve tell us about distance or displacement.

Required solution:

$:\implies \sf Distance \: = Area \: under \: curve \\ \\ :\implies \sf s \: = Area \: under \: curve \\ \\ :\implies \sf s \: = Area \: of \: rectangle \\ \\ :\implies \sf s \: = Length \times Breadth \\ \\ :\implies \sf s \: = (30-0) \times (10-0) \\ \\ :\implies \sf s \: = 30 \times 10 \\ \\ :\implies \sf s \: = 300 \: m \\ \\ :\implies \sf Distance \: = 300 \: metres$

Henceforth, distance = 300 metres