Physics, asked by baliyandevansh20, 18 days ago

please answer it fast​

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Answered by Anonymous
1

 \huge \fbox \red{Solution:}

 \mathfrak \blue{Answer:}

 \sf{W(CO2) \: = \: 336g}

 \mathfrak \green{Explanation:}

Reaction of combustion of propane is written as

 \fbox{\sf{C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)}}

1 mole of propane produces 3 moles of carbon dioxide.

 \sf{3 × n(propane) ⇒ n(CO2)}

 \sf{3 × 112/44 ⇒ W(CO2) /44}

 \sf{W(CO2) = 3 × 113 × 44 / 44}

 \sf{W(CO2) = 336g}

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