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a) Cu do not react with dilute sulphuric acid as it comes behind hydrogen in the reactivity series. But with concentrated H
2
SO
4
it reacts to form CuSO
4
and SO
2
is evolved.
Cu+2H
2
SO
4
(conc)→CuSO
4
+SO
2
+2H
2
O
b) Since Fe is more reactive than Cu. It will displace Cu from CuSO
4
and form FeSO
4
. A color change of blue to light green will occur.
Fe+CuSO
4
→FeSO
4
+Cu
Explanation:
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