Math, asked by yash0000, 1 year ago

PLEASE ANSWER IT FAST GUYS . I WILL GIVE YOU 30 POINTS.....

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Answered by siddhartharao77
3
Given Dividend = 6123

Given that divisor = remainder.

Let the divisor be x, then the remainder will also be x.

Given that remainder is half the divisor = x/2  ------ (1) 


We know that Dividend = Divisor * Quotient + Remainder

6123 = x * x + x/2

It can be written as,

6123 =  \frac{x^2}{1} +  \frac{x}{2}

6123 = 2x^2 + x/2

6123 * 2 = 2x^2 + x

12246 = 2x^2 + x

2x^2 + x - 12246 = 0

2x^2 - 156x + 157x - 12246 = 0

2x(x - 78) + 157(x - 78) = 0

(2x + 157)(x - 78) = 0

x = -157/2 (or) x = 78
.
Since x cannot be -ve, so x = 78.


Therefore the divisor = 78.


Hope this helps!

siddhartharao77: Okk Shadow20. Tell me. I will listen.
shadow20: you have considered x*x as 2x^2 which is wrong
siddhartharao77: That is not x * x bro. It is the lcm as 2.
shadow20: its just x^2
siddhartharao77: In that lcm is 2.
shadow20: okay
shadow20: icm?
siddhartharao77: Now check the answer once. It have modified that step
Answered by Anonymous
0
Hi,


Please see the attached file!


Thanks
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