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Given : a5 + a9 = 30
a25 = 3(a8)
a5 = a + 4d
a9 = a + 8d
a + 4d + a + 8d = 30
2a + 12d = 30 - (i)
a25 = 3(a + 7d)
a + 24d = 3a + 21d
0 = 3a + 21d - a - 24d
0 = 2a - 3d - (ii)
from i and ii :-
using canceling method -
2a + 12d = 30
2a - 3d = 0
- + -
answer = 15d = 30
= d = 2
putting value of d in equation ii
0 = 2a - 3(2)
0 = 2a - 6
6 = 2a
3 = a
Therefore:-
AP - 3 , 5 , 7 ....
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