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If x+y=5 and xy=4 then the value of x^3 + y^3 ?
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Given
Value of (x + y) = 5
Value of xy = 4
To find
Value of (x³ + y³)
Solution
As we know that,
➥ x³ + y³ = (x + y)³ - 3xy(x + y)
Putting values we get :
⟼ x³ + y³ = (5)³ - 3 × 4(5)
⟼ x³ + y³ = 125 - (3 × 20)
⟼ x³ + y³ = 125 - 60
⟼ x³ + y³ = 60
Therefore,
Required value of (x³ + y³) = 60 .
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Some more identities :
- (x + y)³ = x³ + y³ + 3xy(x + y)
- (x - y)³ = x³ - y³ - 3xy(x - y)
- x³ - y³ = (x - y)³ + 3xy(x - y)
- x³ + y³ = (x + y)(x² - xy + y²)
- x³ - y³ = (x - y)(x² + xy + y²)
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