Question

please answer it fast in marathi​

Answer 1

Answer:

-6 or 1

Step-by-step explanation:

1x^2 + 5x - 6 = 0

quadratic expression

so sri dhar aacharya fomula =

let a = 1

b = 5

x = x

c = -6

x = (-b +/-$\sqrt{b^2 - 4ac}$)/2a

x = (-5 +/-$\sqrt{5^2 - 4(1)(-6)}$)/2(1)

x = (-5 +/-$\sqrt{25+ 24)}$)/2(1)

x = (-5 +/-$\sqrt{49}$)/2

x = (-5 +/-7)/2

so x = -6{(-5 - 7)/2 = -12/2 = -6} or  x = 1{(-5 +7)/2 = 2/2 = 1}

PLZ BRAINLIEST MARK