Physics, asked by Anonymous, 3 months ago

Please answer it fast it's urgent
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Answers

Answered by Atαrαh

Solution :-

As per the given data ,

Initial velocity (u) = 10 m/s
Retardation (a) = - 1.25 m/s ²
Final velocity (v) = 0 m/s ( as it comes to rest )

As the car is moving with uniform acceleration throughout it's motion we can use the third equation of motion to find distance and first equation of motion to find time

As per the third equation of motion ,

➜ v² = u ² + 2as

On rearranging ,

➜ s = v² - u² / 2a

➜ s = 0 - 100 / - 2 x 1.25

➜ s = - 100 / - 2.5

➜ s = 40 m

The distance covered by the car is 40 m

Now ,

By using first equation of motion ,

➜ v = u + at

On rearranging ,

➜ t = v - u / a

➜ t = 0 - 10 / 1.25

➜ t = 8 sec

The time taken by the car to stop is 8 sec

Answered by Anonymous

Given :-

$\\$

• Initial velocity (u) = 10 m/s

• Retardation (a) = - 1.25 m/s ²

• Final velocity (v) = 0 m/s

$\\$

To Find :-

$\\$

• Distance covered, s

• Time taken, t

$\\$

Solution :-

$\\$

$\underline{\:\textsf{ Using 3rd equation of motion :}}$

$\dashrightarrow \sf v^2= u^2+2as\\ \\ \dashrightarrow \sf (0)^2= (10)^2+2\times -1.25\times s\\ \\ \dashrightarrow \sf 0= 100-2.5\times s\\ \\ \dashrightarrow \sf \cancel{\dfrac{100}{2.5}}= s\\ \\ \dashrightarrow \sf 40= s$

$\\$

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$\underline{\:\textsf{ Using 1st equation of motion :}}$

$\sf \dashrightarrow v = u + at \\\\ \sf \dashrightarrow t= \dfrac{v-u}{a} \\\\ \sf \dashrightarrow t = \dfrac{0 - 10}{1.25} \\\\\\ \sf \dashrightarrow a = \dfrac{-10}{1.25} \\\\ \sf \dashrightarrow t = 8$