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given : A,B and C are interior angles of atriangle
Step-by-step explanation:
A+B+C= 180
divide 2 on both sides
A+B+C / 2 = 180/2
(A+B/2) + C/2 = 90
A+B/2. = 90-C/2
applying tan on both sides
tan(A+B/2) = tan (90-C/2)
tan (A+B/2) = cot c/2 { since tan ∅ = cot (90-∅)
hence proved ..
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