Question

please answer it fast...........please are urgent hai please kar do n solve..........................

Answer 1

*My question:*

which standard u r in

Answer 2

Answer:

Q3. i) 0.11

ii) 0.0204

Q4. i) 4.594 ×10^(-10)

ii) 10368701.01

Step-by-step explanation:

Q3. i ) (0.11×0.0625×0.04)/ (0.01×0.25)

= (2.75×10^(-4)) / ( 2.5 × 10^(-3))

= (2.75/ 2.5) × 10^(-4) × 10^ (3)

= 1.1 × 10 ^( -1)

= 0.11

ii) ((1÷3)^(-1) +(1÷4)^( -1))^(-2)

= ((1 ^(-1)/3 (-1)) + (1^(-1)/4 (-1))^(-2)

= (3+4)^(-2)

= 0.0204

Q4. i) ( (9^3)^(-2)) ×(4^(-6))

= ( (729)^(-2)) × ( 4^(-6))

= (1.882×10^(-6))×(2.441×10^(-4))

= 4.594× 10^(-10)

ii) ( (6^(-2))^(-1)) ÷ (6^ (-7))

( (0.027)^(-1)) ÷ (6^(-7))

= 37.0370 ÷( 3.572 ×(10^(-6)))

= 10368701.01