Question

Please answer it fast question number 2 answer it fast

Answer 1

Question:-

In ΔABC, AD is the perpendicular bisector of BC (see the given figure). Show that ΔABC is an isosceles triangle in which AB = AC.

Step by Step explanation:-

Given :

In ΔABC, AD is the perpendicular bisector of BC.

To Prove :

ΔABC is an isosceles triangle in which AB = AC.

Solution :

In ΔADC and ΔADB,

AD = AD (Common)

∠ADC =∠ADB (Each 90º)

CD = BD (AD is the perpendicular bisector of BC)

∴ ΔADC ≅ ΔADB (By SAS congruence rule)

∴AB = AC (By CPCT)

Therefore, ABC is an isosceles triangle in which AB = AC.

Hence proved

Additional Information

• A line which cuts a line segment into two equal parts at 90° is known as perpendicular bisector.

• An isosceles triangle is a triangle with (at least) two equal sides.

• SSS (side-side-side) All three corresponding sides are congruent.
• SAS (side-angle-side) Two sides and the angle between them are congruent.
• ASA (angle-side-angle)Two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent

(Figure in attachment)

Answer 2

$\huge\color{orange}\star \: \tt\pink{Answer} \: \star$

$\large\underline\mathrm{GiVeN}$

• AD ⊥ BC

$\large\underline\mathrm{To\:PrOvE }$

• AB = AC

$\large\underline\mathrm{SoLuTiOn}$

In△ABD and △ACD

∠BAD = ∠CAD [ AD Bisects ∠A ]

AD = AD [ Common ]

∠ADB = ∠ ADC = 90° [ Given ]

So, △ABD ≅ △ACD [by ASA rule ]

So, AB = AC [ by CPCT ]

or, △ABC is an isosceles triangle.

$<marquee>$hope it helps you.....✌✌