Math, asked by kbheemashankar23, 2 months ago

please answer it fastly​

Attachments:

Answers

Answered by srishtigupta26
0

Answer:

ye konsi language h???

I can't understand sorry!!!!!!

Answered by PiratedHelper
0

Answer:

The graph of y+x2=0 lies in Q3 and Q4.

Step-by-step explanation:

To solve this equation, the first step would be to simplify the equation y+x2=0 by isolating y as follows:

y+x2=0

y+x2−x2=0−x2

To isolate y, we subtracted x2 from both sides of the equation.

This means that y can never be a positive number, only 0 or a negative number, since we stated that y equals a negative value; −x2.

Now to graph it out:

graph{y=-x^2 [-19.92, 20.08, -16.8, 3.2]}

We can test that the graph is correct simply by using a value for x:

x=2

y=−(22)

y=−4

Because the graph is symmetrical, when y=−4, x=2orx=−2.

And to answer your question, we can see that when we plot the equation out on the graph, the line falls in quadrants 3 and 4.

Please mark as Brainliest

Similar questions