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min value when all elements of set A are common with set B=6
max value when no elements are common=9
max value when no elements are common=9
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n(A)+n(B)=N(AUB)
3+6=n(AUB)
n(AUB)=9
so maximum no of elements are 9 in n(AUB)
3+6=n(AUB)
n(AUB)=9
so maximum no of elements are 9 in n(AUB)
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