Question

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Answer 1

Answer:

this is the your answer.

Step-by-step explanation:

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Answer 2

Answer:

${2}^{n} = \sqrt[3]{8} \div ( {2}^{3} ) {}^{ \frac{2}{3} } \\ = {8}^{ \frac{1}{3} } \div 2 {}^{2} \\ = ({2}^{3} ) {}^{ \frac{1}{3} } \times 2 {}^{ - 2} \\ = 2 {}^{1} \times {2}^{ - 2} \\ = 2 {}^{(1 - 2)} \\ = 2 {}^{ - 1} \\ base \: are \: equal \\ so \\ \: n \: = - 1$