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Solution.
Let the ages of A and B are 5x and 7x respectively.
Now, four years later or now...
Age of A be (5x+4) and Age of B be (7x+4).
Thus, ATQ..
5x+4 ÷ 7x+4 = 3/4
4 (5x+4) = 3(7x+4)
20x + 16 = 21x + 12
16-12 = 21x - 20x
➡➡ x = 4....
B = 7 × 4 = 28.
So age of B is 28 years...
Hence,, Option b.) is correct.
HOPE THIS WILL HELP YOU. ✌✌☺
Let the ages of A and B are 5x and 7x respectively.
Now, four years later or now...
Age of A be (5x+4) and Age of B be (7x+4).
Thus, ATQ..
5x+4 ÷ 7x+4 = 3/4
4 (5x+4) = 3(7x+4)
20x + 16 = 21x + 12
16-12 = 21x - 20x
➡➡ x = 4....
B = 7 × 4 = 28.
So age of B is 28 years...
Hence,, Option b.) is correct.
HOPE THIS WILL HELP YOU. ✌✌☺
rock1416:
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let age be
5x & 7x
4 years later
5x+4 and 7x+4
New ratio = 3:4
sol.
5x+4 / 7x+4 = 3/4
cross multipled
4(5x+4) = 3(7x+4)
20x+16 = 21x+12
21x-20x = 16-12
x = 4
put value At B
7x
7*4=28
28 Ans
5x & 7x
4 years later
5x+4 and 7x+4
New ratio = 3:4
sol.
5x+4 / 7x+4 = 3/4
cross multipled
4(5x+4) = 3(7x+4)
20x+16 = 21x+12
21x-20x = 16-12
x = 4
put value At B
7x
7*4=28
28 Ans
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