Question

Please answer it for me. Please be fast. (100points)

Answer 1

Step-by-step explanation:

Here,

15)

x² - 2√2x + 1

(2√2)² - 2√2×2√2 +1

8 - 8 +1

9-8

1. answer

16)

x²+x - 6 = 0

x² - 3x + 2x - 6 = 0

X ( X - 3) + 2( X - 3) = 0

( X - 3) ( 2 + X ) = 0

So,

x - 3 = 0

x = 3

and,

x + 2 = 0

x = - 2

answer

Answer 2

No.15, 16, 17 can be solved in a new way. We can solve them in easier ways.

15

Can you notice the first two terms x²-2√2x has x-2√2 as a factor? You can say that p(2√2)=1 by the remainder theorem.

Ans: (b)1

16

α+β is given by -b/a. And αβ is c/a.

We get α+β=-1, αβ=-6. Such numbers are two and negative three.

Ans: (c)2, -3

17

Again, we get α+β=-5/2 and αβ=-3/2. It is difficult to find such numbers.

We have 2α+2β=-5, 4αβ=-6. Such numbers, here 2α and 2β, are -6 and 1.

What we want are α and β. Divide both by two, we have -3 and 1/2 as solutions.

Ans: (b)1/2, -3