Question

please answer it guys
its from lesson - sequences and series​

Answer 1

Answer:

t4=a+(n-1)d

16=a+(4-1)d

16=a+3d.................(1)

t9=a+8d

512=a=+8d...............(2)

subtracting (1)from (2)

496=5d

so, d=496÷5=99.2

so, put this in eqn (1)

16=a+3×99.2

a=281.6

s10=a+(n-1)d

=281.6+9×99.2

=281.6+892.8

=1184.4