Question

please answer it guys its urgent ​

Answer 1

Answer:

1/2

Step-by-step explanation:

sec A=2x and tan A=2/x

2(x²-1/x²)

2(x+1/x)(x-1/x)

4/2(x+1/x)(x-1/x)

1/2(2x+2/x)(2x-2/x)

1/2(sec A+tanA)(sec A-tan A)

(sec²A-tan²A)/2

1/2