Question

please answer it hurry​

Answer 1

please see the attachment

Answer 2

$\frac{1}{1 + \sqrt{2} } = - 1 + \sqrt{2} \\ \frac{1}{ \sqrt{2} + \sqrt{3} } = - \sqrt{2} + \sqrt{3} \\ \frac{1}{ \sqrt{3} + \sqrt{4} } = - \sqrt{3} + \sqrt{4} \\ \frac{1}{ \sqrt{4} + \sqrt{5} } = - \sqrt{4} + \sqrt{5} \\ \frac{1}{ \sqrt{5} + \sqrt{6} } = - \sqrt{5} + \sqrt{6} \\ \frac{1}{ \sqrt{6} + \sqrt{7} } = - \sqrt{6} + \sqrt{7} \\ \frac{1}{ \sqrt{7} + \sqrt{8} } = - \sqrt{7} + \sqrt{8} \\ \frac{1}{ \sqrt{8} + \sqrt{9} } = - \sqrt{8} + \sqrt{9} \\ \\ putting \: all \: together \\ \\ - 1 + \sqrt{2} - \sqrt{2} + \sqrt{3} - \sqrt{3} + \sqrt{4} - \sqrt{4} + \sqrt{5} - \sqrt{5} + \sqrt{6} - \sqrt{6} + \sqrt{7} - \sqrt{7} + \sqrt{8} - \sqrt{8} + \sqrt{9} = 2 \\ \\ - 1 + \sqrt{9} = 2 \\ \\ - 1 + 3 = 2 \\ \\ 2 = 2$