Question

please answer it I need help please

Answer 1

In rt ∆ADB,

sin x = AD / AB

= 4/5

In rt ∆ADC,

sin y = AD/AC

= 4/12 = 1/3

sin x + sin y = 4/5 + 1/3

= 19/15

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Answer 2

sin x= 4/5

sin y = 4/12

sin x + sin y = 4/5 + 4/12 = 4/5 + 1/3

=(12+5)/15

= 17/15