Question

Please answer it.........
If A =60° and B=30°,show that:
(sin A cos B + cos A sin B)^2 +(cos A cos B - sin A sin B)^2 = 1​

Answer 1

Step-by-step explanation:

use formulas

• Sin(A+B)=SinA.cosB+cosA.sinB
• cos(A+B)=cosAcosB-sinAsinB

simplifying the equation we get

=Sin(A+B)^2+Cos(A+B)^2

putting values of A and B we get

=Sin(90)^2+cos(90)^2

=(1)^2+0

=1

Hence proved