Question

please answer it . if u can so.please​

Answer 1

Question :

If the area of a rectangle is 1 m² and its breadth is 80 cm, find its length.

Given :

• Area of rectangle = 1 m²
• Breadth of rectangle = 80 cm

To find :

• Length of rectangle

Knowledge required :

• Formula of area of rectangle :-

⠀⠀⠀⠀Area of rectangle = l × b

where,

• l = length of the rectangle
• b = breadth of the rectangle

• Unit conversion :-

⠀⠀⠀1 cm = 1/100 m

Divide the value by 100 to convert it from cm into m.

Solution :

Firstly, convert the breadth of rectangle from cm into m.

⠀⠀⠀⇒ Breadth = 80 cm

⠀⠀⠀⇒ Breadth = 80/100

⠀⠀⠀⇒ Breadth = 8/10 = 0.8 m

• Breadth of rectangle = 0.8 m

Using formula,

• Area of rectangle = l × b

⠀⠀⠀⇒ 1 = l × 0.8

⠀⠀⠀⇒ 1/0.8 = l

⠀⠀⠀⇒ 10/8 = l

⠀⠀⠀⇒ 1.25 = l

Length = 1.25 m

Length of rectangle = 1.25 m or 125 cm

━━━━━━━━━━━━━━━

⠀⠀⠀⠀⠀⠀Verification :-

Substitute the value of length 1 = l × 0.8

Lhs = 1

Taking Rhs,

⠀⠀⠀⇒ l × 0.8

⠀⠀⠀⇒ 1.25 × 0.8

⠀⠀⠀⇒ 1

Rhs = 1

Lhs = Rhs

Hence, verified.

Answer 2

Given: Area of the rectangle is 1m² & breadth of the rectangle is 80cm.

⠀⠀⠀⠀

Need to find: Length of the rectangle?

⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀

❍ Let's consider length of the rectangle as x.

⠀⠀⠀⠀⠀

As we know that,

⠀⠀⠀⠀⠀

• $\boxed{ \frak{\pink{1{m}^{2} = 10000cm}}}$

⠀⠀⠀⠀

$\begin{gathered}\star\:{\underline{\boxed{\frak{Area_{\:(rectangle)} = Length \times Breadth}}}}\\\\\\ \bf{\dag}\:{\underline{\frak{Putting\:given\:values\:in\:formula,}}}\\\\\\ :\implies\sf 10000 = 80 \times x\\\\\\ :\implies\sf 10000 = 80x\\\\\\ :\implies\sf x= \cancel{\dfrac{10000}{80}}\\\\\\ :\implies\sf x = 125\\\\\\ \implies{\underline{\boxed{\frak{\purple{x = 125cm}}}}}\:\bigstar\\\\\end{gathered}$

⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━

Therefore,

⠀⠀⠀⠀⠀

Length of rectangular park, x = 125cm

$\therefore\:{\underline{\sf{Hence,\: Length \: of \: rectangular \: park \: is \: {\bf 125cm} \: {respectively}.}}}$

⠀⠀⠀⠀

$\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}$