Question

please answer it if u have a brain

Answer 1

Answer:

Theta = 60°

Step-by-step explanation:

In the attachment.. Hope its helpful..

Answer 2

Given that :

$3 { \cos }^{2} \alpha = { \sin}^{2} \alpha \\ \\ = > 3 = \frac{ { \sin }^{2} \alpha }{ { \cos }^{2} \alpha } \\ \\ = > { \tan}^{2} \alpha = 3 \\ \\On \: taking \: square \: root \: both \: the \: side :\\ \\ = > \sqrt{ { \tan}^{2} \alpha } = \sqrt{3} \\ \\ = > \tan\alpha = \sqrt{3} \\ \\ = > \alpha = { \tan }^{ - 1} \sqrt{3} \\ \\ As \: we \: know \: that: \: { \tan }^{ - 1} \sqrt{3} = 60 \\ \\ = > \alpha = 60$