Question

please answer it if you answer it then I mark as brainlist please help me and it's very urgent special products and expansion​

Answer 1

Step-by-step explanation:

4x²y²+4xy-2.8xy-2.8

4x²y²+1.2xy-2.8

Answer 2

Answer:

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4x²y² + 1.2xy - 2.8

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Step by step explanation:

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As per the provided information in the question, We have :

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• (2xy - 1.4)(2xy + 2)

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We are asked to expand and find the product of these two.

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Here we will multiply (or expand) two linear binomials, i.e :

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• (2xy - 1.4)
• (2xy + 2)

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$\longmapsto \rm (2xy - 1.4)(2xy + 2)$

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First, We will expand the bracket.

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$\longmapsto \rm 2xy (2xy + 2)- 1.4(2xy + 2)$

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Multiplying the term with the terms in the brackets.

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$\longmapsto \rm 4 {x}^{2} {y}^{2} + 4xy- 2.8xy - 2.8$

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Combining like terms.

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$\longmapsto \rm 4 {x}^{2} {y}^{2} + 1.2xy - 2.8$

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∴ (2xy - 1.4)(2xy + 2) = 4x²y² + 1.2xy - 2.8

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$\rule{200}2$

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Now, To verify this, We will factorise the resultant.

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$\longmapsto \rm 4 {x}^{2} {y}^{2} + 1.2xy - 2.8$

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Factorising the expression.

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$\longmapsto \rm 2xy (2xy + 2)- 1.4(2xy + 2)$

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$\longmapsto \rm (2xy - 1.4)(2xy + 2)$

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Henceforth, Verified!