Physics, asked by priyatiwari7375, 3 months ago

Please answer it immediately​

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Answered by sudhakarmadugula123
0

\color{blue}{Answer:}

CP = 2 + 4 = 6μF

1/C =1/6 + 1/6 = 2/6 = 1/3 or C=3μF

Total charge

Q = CV = 3 × 12 = 36μC

voltage across 6μF capacitor = 36μC/6μF = 6V

∴ Voltage across each of 2μF and 4μF 

capacitors

     = 12V − 6V

V = 6V

Hope it helps you

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