Question

Please answer it immediately​

Answer 1

$\color{blue}{Answer:}$

CP = 2 + 4 = 6μF

1/C =1/6 + 1/6 = 2/6 = 1/3 or C=3μF

Total charge

Q = CV = 3 × 12 = 36μC

voltage across 6μF capacitor = 36μC/6μF = 6V

∴ Voltage across each of 2μF and 4μF 

capacitors

     = 12V − 6V

V = 6V

Hope it helps you