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CP = 2 + 4 = 6μF
1/C =1/6 + 1/6 = 2/6 = 1/3 or C=3μF
Total charge
Q = CV = 3 × 12 = 36μC
voltage across 6μF capacitor = 36μC/6μF = 6V
∴ Voltage across each of 2μF and 4μF
capacitors
= 12V − 6V
V = 6V
Hope it helps you
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