Question

Please answer it in easy method​

Answer 1

Acceleration (a) = -6m/s²

Time (t) = 2s

Final velocity (v) = 0m/s

Let the initial velocity be (u)

Let the distance be (s)

v = u +at

So , (o) = u + (-6) (2)

So, (u) = 12 m/s

Now, s = ut + (½) at²

So, s = 12(2) + (½) (-6) (2²)

So, s = 24-2

so ,s = 12 m

Thus , distance traveled is 12m.

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