Question

Please answer it, it's urgent

Answer 1

Answer:

a) X and Y only

Answer 2

Answer:

sorry for spam

sinθ + cosθ−1sinθ−cosθ+1 < /p > < p > < /p > < p > =(sinθ+cosθ−1sinθ−cosθ+1)×(sinθ+cosθ+1sinθ+cosθ+1) < /p > < p > < /p > < p > =(sinθ+cosθ−1sinθ+1−cosθ)×(sinθ+cosθ+1sinθ+1+cosθ) < /p > < p > < /p > < p > =(sinθ+cosθ)2−12(sinθ+1)2−cos2θ < /p > < p > < /p > < p > =sin2θ+cos2θ+2sinθcosθ−1sin2θ+1+2sinθ−cos2θ < /p > < p > < /p > < p >   < /p > < p > < /p > < p > Since, sin2θ+cos2θ=1 < /p > < p > < /p > < p >   < /p > < p > < /p > < p > Therefore, < /p > < p > < /p > < p > =1+2sinθcosθ−11−cos2θ+1+2sinθ−cos2θ < /p > < p > < /p > < p > =2sinθcosθ2−2cos2θ+2sinθ < /p > < p > < /p > < p > =sinθcosθ1−cos2θ+sinθ < /p > < p > < /p > < p > =sinθcosθsin2θ+sinθ < /p > < p > < /p > < p > =cosθsinθ+1 < /p > < p > < /p > < p > =cosθ1+cosθsinθ < /p > < p > < /p > < p > =secθ+tanθ < /p > < p > < /p > < p > =(secθ+tanθ)×(secθ−tanθsecθ−tanθ) < /p > < p > < /p > < p > =secθ−tanθsec2θ−tan2θ < /p > < p > < /p > < p >   < /p > < p > < /p > < p > We know that < /p > < p > < /p > < p > sec2θ−tan2θ=1 < /p > < p > < /p > < p >   < /p > < p > < /p > < p > Therefore, < /p > < p > < /p > < p > =secθ−tanθ1 < /p > < p > < /p > < p > < /p > < p >sinθ+cosθ−1sinθ−cosθ+1</p><p></p><p>=(sinθ+cosθ−1sinθ−cosθ+1)×(sinθ+cosθ+1sinθ+cosθ+1)</p><p></p><p>=(sinθ+cosθ−1sinθ+1−cosθ)×(sinθ+cosθ+1sinθ+1+cosθ)</p><p></p><p>=(sinθ+cosθ)2−12(sinθ+1)2−cos2θ</p><p></p><p>=sin2θ+cos2θ+2sinθcosθ−1sin2θ+1+2sinθ−cos2θ</p><p></p><p> </p><p></p><p>Since, sin2θ+cos2θ=1</p><p></p><p> </p><p></p><p>Therefore,</p><p></p><p>=1+2sinθcosθ−11−cos2θ+1+2sinθ−cos2θ</p><p></p><p>=2sinθcosθ2−2cos2θ+2sinθ</p><p></p><p>=sinθcosθ1−cos2θ+sinθ</p><p></p><p>=sinθcosθsin2θ+sinθ</p><p></p><p>=cosθsinθ+1</p><p></p><p>=cosθ1+cosθsinθ</p><p></p><p>=secθ+tanθ</p><p></p><p>=(secθ+tanθ)×(secθ−tanθsecθ−tanθ)</p><p></p><p>=secθ−tanθsec2θ−tan2θ</p><p></p><p> </p><p></p><p>Weknowthat</p><p></p><p>sec2θ−tan2θ=1</p><p></p><p> </p><p></p><p>Therefore,</p><p></p><p>=secθ−tanθ1</p>

i can't understand this answer which you answered my question.