Please answer it
it's urgent
Attachments:
Answers
Answered by
0
Given a + b + c = 0
⇒ a3 + b3 + c3 = 3abc → (1)
Consider, (a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc = 3 [From (1)]
I hope this help u
⇒ a3 + b3 + c3 = 3abc → (1)
Consider, (a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc = 3 [From (1)]
I hope this help u
Similar questions