Please answer it it's urgent.
Attachments:

Answers
Answered by
1
yes it is Definitely correct as it is an identity
Anonymous:
what
Answered by
4
Hey Hanu ,
Here is your solution :
Given,
⇒ ( a + b + c ) = 0
⇒ a + b = -c ------ ( 1 )
By cubing both sides ,
⇒ ( a + b )³ = ( -c )³
⇒ a³ + b³ + 3 ab ( a + b ) = - c³
By putting back the value of ( a + b ) ,
⇒ a³ + b³ + 3 ab ( - c ) = - c³
⇒ a³ + b³ - 3abc = -c³
⇒ a³ + b³ + c³ - 3 abc = 0
⇒ a³ + b³ + c³ = 3 abc
Proved !!
Identities used to prove it :
= ( a + b )³
= ( a + b ) ( a + b ) ( a + b )
= ( a² + ab + ab + b² ) ( a + b )
= ( a² + 2 ab + b² ) ( a + b )
= ( a³ + a²b + 2 a²b + 2 ab² + ab² + b³ )
= ( a³ + 3 a²b + 3 ab² + b³ )
= a³ + b³ + 3 a²b + 3 ab²
= a³ + b³ + 3 ab ( a + b ).
Here is your solution :
Given,
⇒ ( a + b + c ) = 0
⇒ a + b = -c ------ ( 1 )
By cubing both sides ,
⇒ ( a + b )³ = ( -c )³
⇒ a³ + b³ + 3 ab ( a + b ) = - c³
By putting back the value of ( a + b ) ,
⇒ a³ + b³ + 3 ab ( - c ) = - c³
⇒ a³ + b³ - 3abc = -c³
⇒ a³ + b³ + c³ - 3 abc = 0
⇒ a³ + b³ + c³ = 3 abc
Proved !!
Identities used to prove it :
= ( a + b )³
= ( a + b ) ( a + b ) ( a + b )
= ( a² + ab + ab + b² ) ( a + b )
= ( a² + 2 ab + b² ) ( a + b )
= ( a³ + a²b + 2 a²b + 2 ab² + ab² + b³ )
= ( a³ + 3 a²b + 3 ab² + b³ )
= a³ + b³ + 3 a²b + 3 ab²
= a³ + b³ + 3 ab ( a + b ).
Similar questions