Question

please answer it my friends​

Answer 1

Step-by-step explanation:

$a = p {(1 + \frac{r}{100}) }^{n}$

As it is compounded Quarterly,

$a = p {(1 + \frac{ \frac{r}{4} }{100}) }^{4n}$

6 months=1/2 years.

THEREFORE,

$a = p {(1 + \frac{ \frac{r}{4} }{100}) }^{4n} \\ = 10000 {(1 + \frac{ \frac{12}{4} }{100} )}^{(4 \times \frac{1}{2} )} \\ = 10000{(1 + \frac{3}{100})}^{2} \\ = 10000 { (\frac{103}{100}) }^{2} \\ = 103 \times 103 \\ = 10609$

ROHIT WOULD RECEIVE 10609/- AFTER MATURITY.....

HOPE IT HELPS