Question

Please answer it , o will mark you brainliest , please , if you give wrong then I will report you .......




.........​

Answer 1

Answer:

Step-by-step explanation:

     6                  3√2+2√3              18√2+12√3

-----------------*-------------------------=----------------------=3√2+2√3

3√2-2√3           3√2+2√3               18-12=6

=3√2+2√3=3√2-(-2√3)

3√2-a√3

a=-2

Answer 2

$\frac{6}{3 \sqrt{2} - 2 \sqrt{3} } = 3 \sqrt{2 } - a \sqrt{3}$

First, rationalizing the denominator

$\frac{6}{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3}}{3 \sqrt{2} + 2 \sqrt{3}} \\ \\ = \frac{18 \sqrt{2} + 12 \sqrt{3} }{ {(3 \sqrt{2}) }^{2} - {(2 \sqrt{3}) }^{2} } \\ \\ = \frac{18 \sqrt{2} + 12 \sqrt{3} }{18 - 12} \\ \\ = \frac{18 \sqrt{2} + 12 \sqrt{3} }{6} \\ \\ = \frac{ \not6(3 \sqrt{2} + 2 \sqrt{3} )}{ \not6} \\ \\ = 3 \sqrt{2} + 2 \sqrt{3}$

Now equate this with 3√2 - a√3

$3 \sqrt{2} + 2 \sqrt{3} = 3 \sqrt{2} - a \sqrt{3} \\ a \sqrt{3} = - 2 \sqrt{3}$

√3 and √3 gets cancel

So,

$a = - 2$