Question

please answer it please​

Answer 1

Answer:

10 is the answer

Step-by-step explanation:

5-2√6+5+2√6/25-24

+2√6 and-2√6 will be cancelled

10/1= 10

Answer 2

$\tt \: \frac{ 1 }{ 5+2 \sqrt{ 6 } } + \frac{ 1 }{ 5-2 \sqrt{ 6 } } \\ \\ \tt \: \frac{5-2\sqrt{6}}{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}+\frac{1}{5-2\sqrt{6}} \\ \\ \tt \: Consider \: \left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right).$

• Multiplication can be transformed into difference of squares using the rule:

$\tt \: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. \\ \\ \tt \: \frac{5-2\sqrt{6}}{5^{2}-\left(2\sqrt{6}\right)^{2}}+\frac{1}{5-2\sqrt{6}} \\ \\ \tt \: \frac{5-2\sqrt{6}}{25-\left(2\sqrt{6}\right)^{2}}+\frac{1}{5-2\sqrt{6}} \\ \\ \tt \: \frac{5-2\sqrt{6}}{25-2^{2}\left(\sqrt{6}\right)^{2}}+\frac{1}{5-2\sqrt{6}} \\ \\ \tt \: \frac{5-2\sqrt{6}}{25-4\times 6}+\frac{1}{5-2\sqrt{6}} \\ \\ \tt \: \frac{5-2\sqrt{6}}{25-24}+\frac{1}{5-2\sqrt{6}} \\ \\ \tt \: \frac{5-2\sqrt{6}}{1}+\frac{1}{5-2\sqrt{6}} \\ \\ \tt \: 5-2\sqrt{6}+\frac{1}{5-2\sqrt{6}} \\ \\ \tt \: 5-2\sqrt{6}+\frac{5+2\sqrt{6}}{\left(5-2\sqrt{6}\right)\left(5+2\sqrt{6}\right)} \\ \\ \tt \: Consider \: \left(5-2\sqrt{6}\right)\left(5+2\sqrt{6}\right).$

• Multiplication can be transformed into difference of squares using the rule:

$\tt \: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2} \\ \\ \tt \: 5-2\sqrt{6}+\frac{5+2\sqrt{6}}{5^{2}-\left(-2\sqrt{6}\right)^{2}} \\ \\ \tt \: 5-2\sqrt{6}+\frac{5+2\sqrt{6}}{25-\left(-2\sqrt{6}\right)^{2}} \\ \\ \tt \: 5-2\sqrt{6}+\frac{5+2\sqrt{6}}{25-\left(-2\right)^{2}\left(\sqrt{6}\right)^{2}} \\ \\ \tt \: 5-2\sqrt{6}+\frac{5+2\sqrt{6}}{25-4\left(\sqrt{6}\right)^{2}} \\ \\ \tt \: 5-2\sqrt{6}+\frac{5+2\sqrt{6}}{25-4\times 6} \\ \\ \tt \: 5-2\sqrt{6}+\frac{5+2\sqrt{6}}{25-24} \\ \\ \tt \: 5-2\sqrt{6}+5+2\sqrt{6} \\ \\ \tt \: 10-2\sqrt{6}+2\sqrt{6} \\ \\ \tt \: 10$

$\sf \: @WildCat7083$