Math, asked by Gohulsundar, 9 months ago

please answer it.pls do with steps​

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Answers

Answered by omshreeprasad16
2

Answer:

B)1000

Step-by-step explanation:

v = u +at

v = 0 + 5 x 10

v = 50 m/s

By converting the given graph into velocity - time graph and obtaining the area underneath it we can find out the distance.

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Answered by rajivrtp
1

Answer:

option (B) 1000 m is correct

Step-by-step explanation:

since initial velocity (u)= 0

for first 10 sec.

velocity at the end of 10 seconds

( v) = at= 5×10

=> v= 50 m/sec

=> distance travelled= v²/2a

= 2500/10= 250m (1)

=> between 10 sec to 20 sec

acceleration= 0

=> the cart is moving with constant

velocity= 50m/sec

=> distance covered by cart between.

10 to 20 sec

= vel × time = 50×10= 500 m. ...........(2)

=> at last the graph is below =>

retardation

applied on the motion ,cart stopat the

end of 30 seconds

=> u= 50m/sec , t = 10 sec => v=0

=> distance covered in this situation

= u²/2a = 2500/10= 250m.................(3)

distance covered by the cart in 30 sec

= (1)+ (2) +(3)

= 1000 metre

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